Simulation Quiz 1

Capturing Complex Response of Structures - Simulation Quiz 1

Complete the simulation and have all the results ready BEFORE starting the quiz.

Once you have finished the exam, click on the 'Mark Complete' button to save your progress and move to the next section.

1 / 15

Consider a situation where the aluminum piece is defined with only linear elastic material (do not set up and solve such a model). In such a case where there is no plasticity and only linear elastic behavior, which option below can be determined without running the simulation?

The aluminum piece will experience the same elastic strains.

The force required to push the die -0.1 mm will be larger.

The aluminum piece will experience lower stresses.

The force required to push the die -0.1 mm will be smaller.

2 / 15

Upon unloading (end of Step 2), which statement below best describes the location of the piece relative to the die?

The die and piece deform but remain in contact.

The die sticks to the piece due to permanent deformation.

The die and piece return to their original, just-touching position.

The die and piece separate due to permanent deformation.

3 / 15

What is the maximum magnitude of force applied to the die to cause the indentation of 0.1mm in the aluminum piece? Select the option that is closest to the result you obtained.

350 N

8000 N

5400 N

0 N

4 / 15

What is the maximum equivalent elastic strain in the piece after indentation (Step 1)? Select the option that is closest to the result you obtained.

0.0001

0.004

0.009

0.4

5 / 15

Review the Directional Deformation in the X-direction of the aluminum piece. Select the best option that is correct.

There is no permanent deformation in the X-direction in the piece at the end of Step 2 since the motion is only in the Y-direction.

The deformation in the X-direction is zero throughout the piece since the piece only moves in the Y-direction.

There is localized deformation in the X-direction at the indentation location.

The maximum deformation in the X-direction is less than 1% of the maximum deformation in the Y-direction.

6 / 15

Review equivalent elastic strain, equivalent stress, and equivalent plastic strain results. Select the best option that is correct.

The maximum equivalent plastic strain history shows an identical trend to the maximum equivalent elastic strain history.

The maximum equivalent stress is always proportional to the maximum equivalent plastic strain.

The maximum equivalent elastic strain does not increase after yielding.

The maximum equivalent elastic strain history shows an identical trend to the maximum equivalent stress history.

7 / 15

Review the Directional Deformation in the Y-direction of the aluminum piece. Select the best option that is correct.

The deformation in the Y-direction is at its maximum magnitude at the end of indentation (Step 1) then goes to zero after unloading (Step 2).

The deformation in the Y-direction is at its maximum magnitude at the end of unloading (Step 2) due to the development of permanent deformation through the simulation.

The deformation in the Y-direction is at its maximum magnitude at the end of indentation (Step 1) and remains constant after unloading (Step 2).

The deformation in the Y-direction is at its maximum magnitude at the end of indentation (Step 1) then decreases but does not go to zero after unloading (Step 2) due to some permanent deformation.

8 / 15

Review the Y-direction Deformation of the aluminum piece at the end of Step 1 (Indentation). The die is moving in the negative Y-direction, but why does some material of the aluminum piece move in the positive Y-direction? Select the best option.

In numerical simulation, force equilibrium considerations require positive deformations to balance the negative deformations.

At the indentation location, the aluminum piece undergoes large plastic strains, which are incompressible.

The use of weak springs in this simulation causes some material to rise, but this effect is negligible and can be ignored.

Contact algorithms require net deformation to be zero, so negative deformations must be balanced by positive deformations.

9 / 15

Review equivalent elastic strain and equivalent plastic strain results. Select the best option that is correct.

The maximum equivalent elastic strain is comparable to the maximum equivalent plastic strain.

During loading, the maximum equivalent plastic strain is much greater than the maximum equivalent elastic strain, but after unloading, the maximum equivalent elastic strain becomes much larger than the maximum equivalent plastic strain.

The maximum equivalent plastic strain is much larger than the maximum equivalent elastic strain.

The maximum equivalent elastic strain is much larger than the maximum equivalent plastic strain.

10 / 15

Consider a situation where the aluminum piece is defined with perfectly-plastic behavior (do not set up and solve such a model). In such a case where the tangent modulus is 0 MPa instead of 500 MPa, which option below can be determined without running the simulation?

The force required to push the die -0.1 mm will be larger.

The force required to push the die -0.1 mm will be smaller.

The aluminum piece will experience the same elastic strains.

The aluminum piece will experience higher stresses.

11 / 15

What is the maximum equivalent stress developed in the aluminum piece at the end of Step 2 (end of simulation)? Select the option that is closest to the result you obtained.

600 MPa

280 MPa

10 MPa

28,500 MPa

12 / 15

Plastic strain and permanent deformation can result when plasticity is included. Select the best option that is a correct statement.

The contour plot of equivalent elastic stress, not equivalent plastic strain, always indicates the locations of permanent deformation.

While deformation is related to strain, permanent deformation cannot be determined solely with contour plots of equivalent plastic strain.

The contour plot of equivalent plastic strain always indicates the locations of permanent deformation.

The contour plot of equivalent elastic strain, not equivalent plastic strain, always indicates the locations of permanent deformation.

13 / 15

What is the maximum Equivalent Plastic Strain developed in the aluminum piece at the end of Step 2?

0.67

0.01

0.04

0

14 / 15

Review the Equivalent Plastic Strain history in the aluminum piece. Select the best option that describes the maximum Equivalent Plastic Strain history.

After unloading, the maximum equivalent plastic strain is a little less than half of its value from the end of Step 1.

The maximum equivalent plastic strain is fully recovered upon unloading.

The maximum equivalent plastic strain is zero throughout the analysis.

The maximum equivalent plastic strain remains the same upon unloading.

15 / 15

What is the maximum Equivalent Stress developed in the aluminum piece at the end of Step 1 (middle of simulation)? Select the option that is closest to the result you obtained.

28,500 MPa

600 MPa

280 MPa

10 MPa

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Capturing Complex Response

Metal Stamping

Total Available Time - 45 mins

Total Number of Questions - 15